(16x^3+4x^2-144)/(4x-8)=0

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Solution for (16x^3+4x^2-144)/(4x-8)=0 equation:


D( x )

4*x-8 = 0

4*x-8 = 0

4*x-8 = 0

4*x-8 = 0 // + 8

4*x = 8 // : 4

x = 8/4

x = 2

x in (-oo:2) U (2:+oo)

(16*x^3+4*x^2-144)/(4*x-8) = 0

16*x^3+4*x^2-144 = 0

4*(4*x^3+x^2-36) = 0

4*x^3+x^2-36 = 0

{ 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 9, -9, 12, -12, 18, -18, 36, -36 }

1

x = 1

4*x^3+x^2-36 = -31

1

-1

x = -1

4*x^3+x^2-36 = -39

-1

2

x = 2

4*x^3+x^2-36 = 0

2

x-2

4*x^2+9*x+18

4*x^3+x^2-36

x-2

8*x^2-4*x^3

9*x^2-36

18*x-9*x^2

18*x-36

36-18*x

0

4*x^2+9*x+18 = 0

DELTA = 9^2-(4*4*18)

DELTA = -207

DELTA < 0

x in { 2}

4*(x-2) = 0

(4*(x-2))/(4*x-8) = 0

x-2 = 0 // + 2

x = 2

x in { 2}

x belongs to the empty set

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